What is the derivative of (\sqrt[3]{x}/(x-3)) ?

The derivative of (\sqrt[3]{x}/(x-3)) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}

What is the first derivative of (\sqrt[3]{x}/(x-3)) ?

The first derivative of (\sqrt[3]{x}/(x-3)) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d}{d x} (x - 3) = 1

Simplify

What is the derivative of (\sqrt[3]{x}/(x-3)) ?
The derivative of (\sqrt[3]{x}/(x-3)) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}
What is the first derivative of (\sqrt[3]{x}/(x-3)) ?
The first derivative of (\sqrt[3]{x}/(x-3)) is (x-3-3\sqrt[3]{x}x^{2/3})/(3x^{2/3)(x-3)^2}