What is the tangent of f(x)=(x-2)(x^2+4),(1,-5) ?

The tangent of f(x)=(x-2)(x^2+4),(1,-5) is y=3x-8

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tangent of f(x)=(x-2)(x^2+4),(1,-5)

tangent of

f (x) = (x - 2) (x^{2} + 4), (1, - 5)

y = 3 x - 8

Solution steps

Find the slope of

f (x) = (x - 2) (x^{2} + 4) : \frac{df ( x )}{d x} = 3 x^{2} - 4 x + 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(1, - 5) : y = 3 x - 8

y = 3 x - 8

What is the tangent of f(x)=(x-2)(x^2+4),(1,-5) ?
The tangent of f(x)=(x-2)(x^2+4),(1,-5) is y=3x-8