What is the d/(dt)(sqrt(6/5-t^2)) ?

The d/(dt)(sqrt(6/5-t^2)) is -(sqrt(5)t)/(sqrt(6-5t^2))

What is the first d/(dt)(sqrt(6/5-t^2)) ?

The first d/(dt)(sqrt(6/5-t^2)) is -(sqrt(5)t)/(sqrt(6-5t^2))

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\frac{d}{d t} (\frac{6}{5} - t^{2})

- \frac{5 t}{6 - 5 t ^{2}}

Solution steps

\frac{d}{d t} (\frac{6}{5} - t^{2})

Apply the chain rule:

\frac{1}{2 \frac{6}{5} - t ^{2}} \frac{d}{d t} (\frac{6}{5} - t^{2})

= \frac{1}{2 \frac{6}{5} - t ^{2}} \frac{d}{d t} (\frac{6}{5} - t^{2})

\frac{d}{d t} (\frac{6}{5} - t^{2}) = - 2 t

= \frac{1}{2 \frac{6}{5} - t ^{2}} (- 2 t)

Simplify

\frac{1}{2 \frac{6}{5} - t ^{2}} (- 2 t) : - \frac{5 t}{6 - 5 t ^{2}}

= - \frac{5 t}{6 - 5 t ^{2}}

What is the d/(dt)(sqrt(6/5-t^2)) ?
The d/(dt)(sqrt(6/5-t^2)) is -(sqrt(5)t)/(sqrt(6-5t^2))
What is the first d/(dt)(sqrt(6/5-t^2)) ?
The first d/(dt)(sqrt(6/5-t^2)) is -(sqrt(5)t)/(sqrt(6-5t^2))