What is the derivative of 1/(x^3-2/(x^2)) ?

The derivative of 1/(x^3-2/(x^2)) is -3/(x^4)+4/(x^3)

What is the first derivative of 1/(x^3-2/(x^2)) ?

The first derivative of 1/(x^3-2/(x^2)) is -3/(x^4)+4/(x^3)

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\frac{d}{d x} (\frac{1}{x ^{3}} - \frac{2}{x ^{2}})

- \frac{3}{x ^{4}} + \frac{4}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{3}} - \frac{2}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x ^{3}}) - \frac{d}{d x} (\frac{2}{x ^{2}})

\frac{d}{d x} (\frac{1}{x ^{3}}) = - \frac{3}{x ^{4}}

\frac{d}{d x} (\frac{2}{x ^{2}}) = - \frac{4}{x ^{3}}

= - \frac{3}{x ^{4}} - (- \frac{4}{x ^{3}})

Simplify

= - \frac{3}{x ^{4}} + \frac{4}{x ^{3}}

What is the derivative of 1/(x^3-2/(x^2)) ?
The derivative of 1/(x^3-2/(x^2)) is -3/(x^4)+4/(x^3)
What is the first derivative of 1/(x^3-2/(x^2)) ?
The first derivative of 1/(x^3-2/(x^2)) is -3/(x^4)+4/(x^3)