(dy)/(dx)=|x-2|

Lösung

\frac{d y}{d x} = ∣ x - 2 ∣

y = \frac{( x - 2 ) ∣ x - 2 ∣}{2} + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = ∣ x - 2 ∣

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = ∣ x - 2 ∣

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int ∣ x - 2 ∣ d x

\int ∣ x - 2 ∣ d x = \frac{( x - 2 ) ∣ x - 2 ∣}{2} + c_{1}

y = \frac{( x - 2 ) ∣ x - 2 ∣}{2} + c_{1}

t an g e n t f (x) = (x^{2} - 4)^{2}

in v erse l a pl a ce \frac{3}{( s + 1 ) ^{3}}

d er i v a t i v e f (x) = \frac{x}{1 + x}

f (x) = 4 x^{3}

\frac{d x}{d t} = x + e^{t}