What is the tangent of y=sqrt(x+5),\at x=11 ?

The tangent of y=sqrt(x+5),\at x=11 is y= 1/8 x+21/8

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tangent of y=sqrt(x+5),\at x=11

tangent of

y = x + 5, at x = 11

y = \frac{1}{8} x + \frac{21}{8}

Solution steps

Find the tangent point:

(11, 4)

Find the slope of

y = x + 5 : \frac{d y}{d x} = \frac{1}{2 x + 5}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(11, 4) : y = \frac{1}{8} x + \frac{21}{8}

y = \frac{1}{8} x + \frac{21}{8}

What is the tangent of y=sqrt(x+5),\at x=11 ?
The tangent of y=sqrt(x+5),\at x=11 is y= 1/8 x+21/8