y^{'''}-12y^{''}+52y^'-96y=0

Lösung

y^{^{'''}} - 12 y^{^{''}} + 52 y^{^{'}} - 96 y = 0

y = c_{1} e^{6 t} + e^{3 t} (c_{2} cos (7 t) + c_{3} sin (7 t))

Schritte zur Lösung

y^{'''} (t) - 12 y^{''} (t) + 52 y^{'} (t) - 96 y = 0

Solve linear ODE:

y = c_{1} e^{6 t} + e^{3 t} (c_{2} cos (7 t) + c_{3} sin (7 t))

y = c_{1} e^{6 t} + e^{3 t} (c_{2} cos (7 t) + c_{3} sin (7 t))

a re a y = e^{x}, y = 7 e^{- x} + 6, x = 0

\frac{d}{d x} (1 0^{x^{2}} + lo g_{10} (∣ 2 + 3 x ∣))

\int_{2}^{8} \frac{3}{x} d x

\int_{0}^{0.5} 7 arccos (x) d x

x \to \infty lim (e^{+ x})