What is the tangent of 4x-32sqrt(x),\at x=4 ?

The tangent of 4x-32sqrt(x),\at x=4 is y=-4x-32

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tangent of 4x-32sqrt(x),\at x=4

tangent of

4 x - 32 x, at x = 4

y = - 4 x - 32

Solution steps

Find the tangent point:

(4, - 48)

Find the slope of

y = 4 x - 32 x : \frac{d y}{d x} = 4 - \frac{16}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

Find the line with slope m=

- 4

and passing through

(4, - 48) : y = - 4 x - 32

y = - 4 x - 32

What is the tangent of 4x-32sqrt(x),\at x=4 ?
The tangent of 4x-32sqrt(x),\at x=4 is y=-4x-32