What is the tangent of y=(t-5)(t^2-3),(2,-3) ?

The tangent of y=(t-5)(t^2-3),(2,-3) is y=-11x+19

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tangent of y=(t-5)(t^2-3),(2,-3)

tangent of

y = (x - 5) (x^{2} - 3), (2, - 3)

y = - 11 x + 19

Solution steps

Find the slope of

y = (x - 5) (x^{2} - 3) : \frac{d y}{d x} = 3 x^{2} - 10 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 11

Find the line with slope m=

- 11

and passing through

(2, - 3) : y = - 11 x + 19

y = - 11 x + 19

What is the tangent of y=(t-5)(t^2-3),(2,-3) ?
The tangent of y=(t-5)(t^2-3),(2,-3) is y=-11x+19