What is the derivative of g(t)=tsqrt(t)\sqrt[3]{t} ?

The derivative of g(t)=tsqrt(t)\sqrt[3]{t} is (11t^{5/6})/6

What is the first derivative of g(t)=tsqrt(t)\sqrt[3]{t} ?

The first derivative of g(t)=tsqrt(t)\sqrt[3]{t} is (11t^{5/6})/6

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derivative of

\frac{11 t ^{\frac{5}{6}}}{6}

Solution steps

Simplify

= \frac{d}{d t} (t^{\frac{11}{6}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{11}{6} t^{\frac{11}{6} - 1}

Simplify

\frac{11}{6} t^{\frac{11}{6} - 1} : \frac{11 t ^{\frac{5}{6}}}{6}

= \frac{11 t ^{\frac{5}{6}}}{6}

What is the derivative of g(t)=tsqrt(t)\sqrt[3]{t} ?
The derivative of g(t)=tsqrt(t)\sqrt[3]{t} is (11t^{5/6})/6
What is the first derivative of g(t)=tsqrt(t)\sqrt[3]{t} ?
The first derivative of g(t)=tsqrt(t)\sqrt[3]{t} is (11t^{5/6})/6