What is the d/(dt)(-1cos(t)+8sin(t)) ?

The d/(dt)(-1cos(t)+8sin(t)) is sin(t)+8cos(t)

What is the first d/(dt)(-1cos(t)+8sin(t)) ?

The first d/(dt)(-1cos(t)+8sin(t)) is sin(t)+8cos(t)

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\frac{d}{d t} (- 1 cos (t) + 8 sin (t))

sin (t) + 8 cos (t)

Solution steps

\frac{d}{d t} (- 1 \cdot cos (t) + 8 sin (t))

Simplify

- 1 \cdot cos (t) + 8 sin (t) : - cos (t) + 8 sin (t)

= \frac{d}{d t} (- cos (t) + 8 sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (cos (t)) + \frac{d}{d t} (8 sin (t))

\frac{d}{d t} (cos (t)) = - sin (t)

\frac{d}{d t} (8 sin (t)) = 8 cos (t)

= - (- sin (t)) + 8 cos (t)

Simplify

= sin (t) + 8 cos (t)

What is the d/(dt)(-1cos(t)+8sin(t)) ?
The d/(dt)(-1cos(t)+8sin(t)) is sin(t)+8cos(t)
What is the first d/(dt)(-1cos(t)+8sin(t)) ?
The first d/(dt)(-1cos(t)+8sin(t)) is sin(t)+8cos(t)