derivative of 2x^4-5x^3+4

Lösung

\frac{d}{d x} (2 x^{4} - 5 x^{3} + 4)

8 x^{3} - 15 x^{2}

Schritte zur Lösung

\frac{d}{d x} (2 x^{4} - 5 x^{3} + 4)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) - \frac{d}{d x} (5 x^{3}) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (4) = 0

= 8 x^{3} - 15 x^{2} + 0

Vereinfache

= 8 x^{3} - 15 x^{2}

h \to 0 lim (- 2 x - h + 3)

\frac{d}{d x} (3 cos (4 x) + sin (4 x))

a re a x = 1, x = 3, y = x^{3} - 8, y = 0

l a pl a ce t r an s f or m 2 (t - 3)^{2} + 15 (t - 3) + 26

\frac{d}{d x} (\frac{8 ( 4 ^{x} )}{x ^{4}})