What is the derivative of e^{-2x}cos(x) ?

The derivative of e^{-2x}cos(x) is -2e^{-2x}cos(x)-e^{-2x}sin(x)

What is the first derivative of e^{-2x}cos(x) ?

The first derivative of e^{-2x}cos(x) is -2e^{-2x}cos(x)-e^{-2x}sin(x)

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\frac{d}{d x} (e^{- 2 x} cos (x))

- 2 e^{- 2 x} cos (x) - e^{- 2 x} sin (x)

Solution steps

\frac{d}{d x} (e^{- 2 x} cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{- 2 x}, g = cos (x)

= \frac{d}{d x} (e^{- 2 x}) cos (x) + \frac{d}{d x} (cos (x)) e^{- 2 x}

\frac{d}{d x} (e^{- 2 x}) = - 2 e^{- 2 x}

\frac{d}{d x} (cos (x)) = - sin (x)

= (- 2 e^{- 2 x}) cos (x) + (- sin (x)) e^{- 2 x}

Simplify

= - 2 e^{- 2 x} cos (x) - e^{- 2 x} sin (x)

What is the derivative of e^{-2x}cos(x) ?
The derivative of e^{-2x}cos(x) is -2e^{-2x}cos(x)-e^{-2x}sin(x)
What is the first derivative of e^{-2x}cos(x) ?
The first derivative of e^{-2x}cos(x) is -2e^{-2x}cos(x)-e^{-2x}sin(x)