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受欢迎的微积分 >

integral of 5cos(sqrt(6x))

解答

\int 5 cos (6 x) d x

解答

\frac{5}{3} (6 x sin (6 x) + cos (6 x)) + C

求解步骤

\int 5 cos (6 x) d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int cos (6 x) d x

使用换元积分法

= 5 \cdot \int cos (u) \frac{1}{6} d u

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \frac{1}{6} \cdot \int cos (u) d u

使用换元积分法

= 5 \cdot \frac{1}{6} \cdot \int cos (v) \cdot 2 v d v

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \frac{1}{6} \cdot 2 \cdot \int cos (v) v d v

使用分布积分法

= 5 \cdot \frac{1}{6} \cdot 2 (v sin (v) - \int sin (v) d v)

\int sin (v) d v = - cos (v)

= 5 \cdot \frac{1}{6} \cdot 2 (v sin (v) - (- cos (v)))

代回

= 5 \cdot \frac{1}{6} \cdot 2 (6 x sin (6 x) - (- cos (6 x)))

化简

5 \cdot \frac{1}{6} \cdot 2 (6 x sin (6 x) - (- cos (6 x))) : \frac{5}{3} (6 x sin (6 x) + cos (6 x))

= \frac{5}{3} (6 x sin (6 x) + cos (6 x))

解答补常数

= \frac{5}{3} (6 x sin (6 x) + cos (6 x)) + C

作图

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