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Beliebt Rechnen >

y^'-y=10te^2t,y(0)=1

Lösung

y^{^{'}} - y = 10 t e^{2} t, y (0) = 1

Lösung

y = - 10 e^{2} (t^{2} + 2 (t + 1)) + (1 + 20 e^{2}) e^{t}

Schritte zur Lösung

y^{'} (t) - y = 10 t e^{2} t

Solve linear ODE:

y = - 10 e^{2} (t^{2} + 2 (t + 1)) + (1 + 20 e^{2}) e^{t}

y = - 10 e^{2} (t^{2} + 2 (t + 1)) + (1 + 20 e^{2}) e^{t}

Graph

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