integral from-1 to 5 of |2x-3|

解答

\int_{- 1}^{5} ∣ 2 x - 3 ∣ d x

\frac{37}{2}

十进制

18.5

求解步骤

\int_{- 1}^{5} ∣ 2 x - 3 ∣ d x

拿掉绝对值

= \int_{- 1}^{\frac{3}{2}} - 2 x + 3 d x + \int_{\frac{3}{2}}^{5} 2 x - 3 d x

\int_{- 1}^{\frac{3}{2}} - 2 x + 3 d x = \frac{25}{4}

\int_{\frac{3}{2}}^{5} 2 x - 3 d x = \frac{49}{4}

= \frac{25}{4} + \frac{49}{4}

化简

\frac{25}{4} + \frac{49}{4} : \frac{37}{2}

= \frac{37}{2}

in v erse l a pl a ce - \frac{2 s + 1}{s ^{2} + 3 s + 2}

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