derivative y=3x+4/x

Lösung

ableitung von

y = 3 x + \frac{4}{x}

3 - \frac{4}{x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (3 x + \frac{4}{x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 3 - \frac{4}{x ^{2}}

\frac{d u + 2 d v}{u + 2 v} = 0

x \to 2 lim (3 x^{2} - 2 x + 1)

d er i v a t i v e f (x) = \frac{7 x ^{2} + 7 x + 7}{x}

t an g e n t y = (x^{(3)} - 4 x)^{(12)} (2)

\frac{\partial}{\partial y} (y + cos^{2} (x))