What is the integral from 2 to infinity of ye^{-5y} ?

The integral from 2 to infinity of ye^{-5y} is (11)/(25e^{10)}

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integral from 2 to infinity of ye^{-5y}

\int_{2}^{\infty} y e^{- 5 y} d y

\frac{11}{25 e ^{10}}

Decimal

0.00001 \dots

Solution steps

\int_{2}^{\infty} y e^{- 5 y} d y

Compute the indefinite integral:

\int y e^{- 5 y} d y = \frac{1}{25} (- 5 e^{- 5 y} y - e^{- 5 y}) + C

Compute the boundaries:

\int_{2}^{\infty} y e^{- 5 y} d y = 0 - (- \frac{11}{25 e ^{10}})

= 0 - (- \frac{11}{25 e ^{10}})

Simplify

= \frac{11}{25 e ^{10}}

What is the integral from 2 to infinity of ye^{-5y} ?
The integral from 2 to infinity of ye^{-5y} is (11)/(25e^{10)}