What is the derivative of y=e^{4x^2}+1 ?

The derivative of y=e^{4x^2}+1 is 8e^{4x^2}x

What is the first derivative of y=e^{4x^2}+1 ?

The first derivative of y=e^{4x^2}+1 is 8e^{4x^2}x

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derivative of

y = e^{4 x^{2}} + 1

8 e^{4 x^{2}} x

Solution steps

\frac{d}{d x} (e^{4 x^{2}} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{4 x^{2}}) + \frac{d}{d x} (1)

\frac{d}{d x} (e^{4 x^{2}}) = e^{4 x^{2}} \cdot 8 x

\frac{d}{d x} (1) = 0

= e^{4 x^{2}} \cdot 8 x + 0

Simplify

= 8 e^{4 x^{2}} x

What is the derivative of y=e^{4x^2}+1 ?
The derivative of y=e^{4x^2}+1 is 8e^{4x^2}x
What is the first derivative of y=e^{4x^2}+1 ?
The first derivative of y=e^{4x^2}+1 is 8e^{4x^2}x