What is the derivative of g(x)=x^2(1-9x) ?

The derivative of g(x)=x^2(1-9x) is 2x-27x^2

What is the first derivative of g(x)=x^2(1-9x) ?

The first derivative of g(x)=x^2(1-9x) is 2x-27x^2

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derivative of

g (x) = x^{2} (1 - 9 x)

2 x - 27 x^{2}

Solution steps

\frac{d}{d x} (x^{2} (1 - 9 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = 1 - 9 x

= \frac{d}{d x} (x^{2}) (1 - 9 x) + \frac{d}{d x} (1 - 9 x) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1 - 9 x) = - 9

= 2 x (1 - 9 x) + (- 9) x^{2}

Simplify

2 x (1 - 9 x) + (- 9) x^{2} : 2 x - 27 x^{2}

= 2 x - 27 x^{2}

What is the derivative of g(x)=x^2(1-9x) ?
The derivative of g(x)=x^2(1-9x) is 2x-27x^2
What is the first derivative of g(x)=x^2(1-9x) ?
The first derivative of g(x)=x^2(1-9x) is 2x-27x^2