integral from 1 to 5 of x^3-5x^2-x+5

Lösung

\int_{1}^{5} x^{3} - 5 x^{2} - x + 5 d x

- \frac{128}{3}

Dezimale

- 42.66666 \dots

Schritte zur Lösung

\int_{1}^{5} x^{3} - 5 x^{2} - x + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} x^{3} d x - \int_{1}^{5} 5 x^{2} d x - \int_{1}^{5} x d x + \int_{1}^{5} 5 d x

\int_{1}^{5} x^{3} d x = 156

\int_{1}^{5} 5 x^{2} d x = \frac{620}{3}

\int_{1}^{5} x d x = 12

\int_{1}^{5} 5 d x = 20

= 156 - \frac{620}{3} - 12 + 20

Vereinfache

156 - \frac{620}{3} - 12 + 20 : - \frac{128}{3}

= - \frac{128}{3}

\frac{d}{d y} (2 1 - y^{2} - (\frac{x}{4})^{2})

d er i v a t i v e f (x) = 17.19 8^{2} - x^{2}

\frac{d}{d x} (e^{x e^{y}})

\frac{d}{d x} (- cot (2 x))

\frac{d}{d x} (cos (x^{2}))