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Beliebt Rechnen >

fläche 4x+y^2=12,x=y

Lösung

fläche

4 x + y^{2} = 12, x = y

Lösung

\frac{64}{3}

+1

Dezimale

21.33333 \dots

Schritte zur Lösung

Stelle

y

nach

4 x + y^{2} = 12

um:

y = 2 3 - x, y = - 2 3 - x

Stelle

y

nach

x = y

um:

y = x

f_{1} (x) = 2 3 - x

f_{2} (x) = - 2 3 - x

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

2 3 - x = - 2 3 - x : x = 3

2 3 - x = x : x = 2

- 2 3 - x = x : x = - 6

= \int_{- 6}^{2} ∣ f_{2} (x) - f_{3} (x) ∣ d x + \int_{2}^{3} ∣ f_{1} (x) - f_{2} (x) ∣ d x

= \int_{- 6}^{2} - 2 3 - x - x d x + \int_{2}^{3} 2 3 - x - (- 2 3 - x) d x

\int_{- 6}^{2} - 2 3 - x - x d x = \frac{56}{3}

\int_{2}^{3} 2 3 - x - (- 2 3 - x) d x = \frac{8}{3}

= \frac{56}{3} + \frac{8}{3}

Vereinfache

= \frac{64}{3}

Graph

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