What is the tangent of f(x)=6sqrt(x),(9,18) ?

The tangent of f(x)=6sqrt(x),(9,18) is y=x+9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=6sqrt(x),(9,18)

tangent of

f (x) = 6 x, (9, 18)

y = x + 9

Solution steps

Find the slope of

f (x) = 6 x : \frac{df ( x )}{d x} = \frac{3}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(9, 18) : y = x + 9

y = x + 9

What is the tangent of f(x)=6sqrt(x),(9,18) ?
The tangent of f(x)=6sqrt(x),(9,18) is y=x+9