y^'+2ty^2=0,y(1)= 1/5

Lösung

y^{^{'}} + 2 t y^{2} = 0, y (1) = \frac{1}{5}

y = \frac{1}{t ^{2} + 4}

Schritte zur Lösung

y^{'} (t) + 2 t y^{2} = 0

Solve separable ODE:

y = \frac{1}{t ^{2} + 4}

y = \frac{1}{t ^{2} + 4}

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