What is the integral from 1 to 2 of 3/(t^4) ?

The integral from 1 to 2 of 3/(t^4) is 7/8

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integral from 1 to 2 of 3/(t^4)

\int_{1}^{2} \frac{3}{t ^{4}} d t

\frac{7}{8}

Decimal

0.875

Solution steps

\int_{1}^{2} \frac{3}{t ^{4}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{2} \frac{1}{t ^{4}} d t

Apply the Power Rule

= 3 [- \frac{1}{3 t ^{3}}]_{1}^{2}

Compute the boundaries:

\frac{7}{24}

= 3 \cdot \frac{7}{24}

Simplify

= \frac{7}{8}

What is the integral from 1 to 2 of 3/(t^4) ?
The integral from 1 to 2 of 3/(t^4) is 7/8