What is the tangent of f(x)= x/(x-3),\at x=0 ?

The tangent of f(x)= x/(x-3),\at x=0 is y=-1/3 x

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tangent of f(x)= x/(x-3),\at x=0

tangent of

f (x) = \frac{x}{x - 3}, at x = 0

y = - \frac{1}{3} x

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

f (x) = \frac{x}{x - 3} : \frac{df ( x )}{d x} = - \frac{3}{( x - 3 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(0, 0) : y = - \frac{1}{3} x

y = - \frac{1}{3} x

What is the tangent of f(x)= x/(x-3),\at x=0 ?
The tangent of f(x)= x/(x-3),\at x=0 is y=-1/3 x