5*(dQ)/(dt)+Q/3 =0

Lösung

5 \cdot \frac{d Q}{d t} + \frac{Q}{3} = 0

Q = e^{\frac{- t - c _{1}}{15}}

Schritte zur Lösung

5 \cdot \frac{d Q}{d t} + \frac{Q}{3} = 0

Solve separable ODE:

Q = e^{\frac{- t - c _{1}}{15}}

Q = e^{\frac{- t - c _{1}}{15}}

f (x) = 5 e^{x}

x^{2} \frac{d y}{d x} + x y = x^{3}

t an g e n t - x^{2} + 4 x, at x = 4

\int x + y + 1 d x

y^{^{'}} = 7 x + y, y (0) = 5