What is the integral of \sqrt[3]{x}(x-3) ?

The integral of \sqrt[3]{x}(x-3) is 3/7 x^{7/3}-9/4 x^{4/3}+C

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integral of \sqrt[3]{x}(x-3)

\frac{3}{7} x^{\frac{7}{3}} - \frac{9}{4} x^{\frac{4}{3}} + C

Solution steps

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int x^{\frac{4}{3}} d x = \frac{3}{7} x^{\frac{7}{3}}

= \frac{3}{7} x^{\frac{7}{3}} - \frac{9}{4} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{7} x^{\frac{7}{3}} - \frac{9}{4} x^{\frac{4}{3}} + C

What is the integral of \sqrt[3]{x}(x-3) ?
The integral of \sqrt[3]{x}(x-3) is 3/7 x^{7/3}-9/4 x^{4/3}+C