What is the tangent of f(x)=sin(sin(x)),0,\at x=pi ?

The tangent of f(x)=sin(sin(x)),0,\at x=pi is y=-x+pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=sin(sin(x)),0,\at x=pi

tangent of

f (x) = sin (sin (x)), 0, at x = π

y = - x + π

Solution steps

Find the tangent point:

(π, 0)

Find the slope of

f (x) = sin (sin (x)) : \frac{df ( x )}{d x} = cos (sin (x)) cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(π, 0) : y = - x + π

y = - x + π

What is the tangent of f(x)=sin(sin(x)),0,\at x=pi ?
The tangent of f(x)=sin(sin(x)),0,\at x=pi is y=-x+pi