derivative of 25x^3-6x^2+7x-88

解

\frac{d}{d x} (25 x^{3} - 6 x^{2} + 7 x - 88)

75 x^{2} - 12 x + 7

解答ステップ

\frac{d}{d x} (25 x^{3} - 6 x^{2} + 7 x - 88)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (25 x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (7 x) - \frac{d}{d x} (88)

\frac{d}{d x} (25 x^{3}) = 75 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (88) = 0

= 75 x^{2} - 12 x + 7 - 0

簡素化

= 75 x^{2} - 12 x + 7