What is laplacetransform 4sin(pit) ?

The answer to laplacetransform 4sin(pit) is (4pi)/(s^2+pi^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

laplacetransform 4sin(pit)

laplace transform

4 sin (π t)

\frac{4 π}{s ^{2} + π ^{2}}

Solution steps

L {4 sin (π t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 L {sin (π t)}

L {sin (π t)} : \frac{π}{s ^{2} + π ^{2}}

= 4 \cdot \frac{π}{s ^{2} + π ^{2}}

Refine

4 \frac{π}{s ^{2} + π ^{2}} : \frac{4 π}{s ^{2} + π ^{2}}

= \frac{4 π}{s ^{2} + π ^{2}}

What is laplacetransform 4sin(pit) ?
The answer to laplacetransform 4sin(pit) is (4pi)/(s^2+pi^2)