9y^{''}+10y=0,y(pi)=1

Lösung

9 y^{^{''}} + 10 y = 0, y (π) = 1

y = \frac{cos ( \frac{10 t}{3} ) ( 1 - sin ( \frac{10 π}{3} ) c _{2} )}{cos ( \frac{10 π}{3} )} + c_{2} sin (\frac{10 t}{3})

Schritte zur Lösung

9 y^{''} (t) + 10 y = 0

Solve linear ODE:

y = \frac{cos ( \frac{10 t}{3} ) ( 1 - sin ( \frac{10 π}{3} ) c _{2} )}{cos ( \frac{10 π}{3} )} + c_{2} sin (\frac{10 t}{3})

y = \frac{cos ( \frac{10 t}{3} ) ( 1 - sin ( \frac{10 π}{3} ) c _{2} )}{cos ( \frac{10 π}{3} )} + c_{2} sin (\frac{10 t}{3})

\frac{d}{d x} (9 x^{\frac{7}{5}} - 5 x^{2} + 1 0^{4})

x \to 0 + lim (- x + 7)

\frac{d ^{2} y}{d x ^{2}} = e^{5 x^{2}}

\frac{d}{d t} (\frac{tan ^{2} ( 3 t )}{t ^{2} + sec ^{2} ( t ) + 1})

t an g e n t f (x) = 4 - x^{2} - ln (\frac{1}{2} x + 1) (0.4)