derivative of 4+ln(x)

Lösung

\frac{d}{d x} (4 + ln (x))

\frac{1}{x}

Schritte zur Lösung

\frac{d}{d x} (4 + ln (x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (4) = 0

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 0 + \frac{1}{x}

Vereinfache

= \frac{1}{x}

y^{^{'}} = y (x y^{6} + 1)

\int_{0}^{17} 2 π x (17 x - x^{2}) d x

x \to a lim (\frac{sec ( x ) - sec ( a )}{x - a})

a re a y = 6 - ln (x + 1), y = ln (x + 1), x = 0

\int \frac{a}{( a ^{2} + x ^{2} ) ^{\frac{3}{2}}} d x