What is the tangent of f(x)=3e^{1-x^2},(1,3) ?

The tangent of f(x)=3e^{1-x^2},(1,3) is y=-6x+9

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tangent of f(x)=3e^{1-x^2},(1,3)

tangent of

f (x) = 3 e^{1 - x^{2}}, (1, 3)

y = - 6 x + 9

Solution steps

Find the slope of

f (x) = 3 e^{1 - x^{2}} : \frac{df ( x )}{d x} = - 6 e^{1 - x^{2}} x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6

Find the line with slope m=

- 6

and passing through

(1, 3) : y = - 6 x + 9

y = - 6 x + 9

What is the tangent of f(x)=3e^{1-x^2},(1,3) ?
The tangent of f(x)=3e^{1-x^2},(1,3) is y=-6x+9