What is (\partial)/(\partial x)(3x^4y^2+1) ?

The answer to (\partial)/(\partial x)(3x^4y^2+1) is 12x^3y^2

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(\partial)/(\partial x)(3x^4y^2+1)

\frac{\partial}{\partial x} (3 x^{4} y^{2} + 1)

12 x^{3} y^{2}

Solution steps

\frac{\partial}{\partial x} (3 x^{4} y^{2} + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{4} y^{2}) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (3 x^{4} y^{2}) = 12 y^{2} x^{3}

\frac{\partial}{\partial x} (1) = 0

= 12 y^{2} x^{3} + 0

Simplify

= 12 x^{3} y^{2}

What is (\partial)/(\partial x)(3x^4y^2+1) ?
The answer to (\partial)/(\partial x)(3x^4y^2+1) is 12x^3y^2