What is the integral of 2sqrt(3x-1) ?

The integral of 2sqrt(3x-1) is 4/9 (3x-1)^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 2sqrt(3x-1)

\int 2 3 x - 1 d x

\frac{4}{9} (3 x - 1)^{\frac{3}{2}} + C

Solution steps

\int 2 3 x - 1 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int 3 x - 1 d x

Apply u-substitution

= 2 \cdot \int \frac{u}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{3} \cdot \int u d u

Apply the Power Rule

= 2 \cdot \frac{1}{3} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 3 x - 1

= 2 \cdot \frac{1}{3} \cdot \frac{2}{3} (3 x - 1)^{\frac{3}{2}}

Simplify

2 \cdot \frac{1}{3} \cdot \frac{2}{3} (3 x - 1)^{\frac{3}{2}} : \frac{4}{9} (3 x - 1)^{\frac{3}{2}}

= \frac{4}{9} (3 x - 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{4}{9} (3 x - 1)^{\frac{3}{2}} + C

What is the integral of 2sqrt(3x-1) ?
The integral of 2sqrt(3x-1) is 4/9 (3x-1)^{3/2}+C