What is the derivative of 1/4 x^3-2x ?

The derivative of 1/4 x^3-2x is (3x^2)/4-2

What is the first derivative of 1/4 x^3-2x ?

The first derivative of 1/4 x^3-2x is (3x^2)/4-2

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\frac{d}{d x} (\frac{1}{4} x^{3} - 2 x)

\frac{3 x ^{2}}{4} - 2

Solution steps

\frac{d}{d x} (\frac{1}{4} x^{3} - 2 x)

Simplify

\frac{1}{4} x^{3} - 2 x : \frac{x ^{3}}{4} - 2 x

= \frac{d}{d x} (\frac{x ^{3}}{4} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{4}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (\frac{x ^{3}}{4}) = \frac{3 x ^{2}}{4}

\frac{d}{d x} (2 x) = 2

= \frac{3 x ^{2}}{4} - 2

What is the derivative of 1/4 x^3-2x ?
The derivative of 1/4 x^3-2x is (3x^2)/4-2
What is the first derivative of 1/4 x^3-2x ?
The first derivative of 1/4 x^3-2x is (3x^2)/4-2