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面积 x=(12-y^2)/4 ,x=y

解答

面积

x = \frac{12 - y ^{2}}{4}, x = y

解答

\frac{64}{3}

+1

十进制

21.33333 \dots

求解步骤

对于

x = \frac{12 - y ^{2}}{4}

将

y

移到一边:

y = 2 - x + 3, y = - 2 - x + 3

对于

x = y

将

y

移到一边:

y = x

f_{1} (x) = 2 - x + 3

f_{2} (x) = - 2 - x + 3

要找到相交点，解

f_{i} (x) = f_{j} (x)

2 - x + 3 = - 2 - x + 3 : x = 3

2 - x + 3 = x : x = 2

- 2 - x + 3 = x : x = - 6

= \int_{- 6}^{2} ∣ f_{2} (x) - f_{3} (x) ∣ d x + \int_{2}^{3} ∣ f_{1} (x) - f_{2} (x) ∣ d x

= \int_{- 6}^{2} - 2 - x + 3 - x d x + \int_{2}^{3} 2 - x + 3 - (- 2 - x + 3) d x

\int_{- 6}^{2} - 2 - x + 3 - x d x = \frac{56}{3}

\int_{2}^{3} 2 - x + 3 - (- 2 - x + 3) d x = \frac{8}{3}

= \frac{56}{3} + \frac{8}{3}

化简

= \frac{64}{3}

作图

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