What is the derivative of y=x^2+4x^3 ?

The derivative of y=x^2+4x^3 is 2x+12x^2

What is the first derivative of y=x^2+4x^3 ?

The first derivative of y=x^2+4x^3 is 2x+12x^2

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derivative of

y = x^{2} + 4 x^{3}

2 x + 12 x^{2}

Solution steps

\frac{d}{d x} (x^{2} + 4 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x^{3})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

= 2 x + 12 x^{2}

What is the derivative of y=x^2+4x^3 ?
The derivative of y=x^2+4x^3 is 2x+12x^2
What is the first derivative of y=x^2+4x^3 ?
The first derivative of y=x^2+4x^3 is 2x+12x^2