What is the tangent of y^2-xy-10=0,(-3,-5) ?

The tangent of y^2-xy-10=0,(-3,-5) is y= 5/7 x-20/7

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tangent of y^2-xy-10=0,(-3,-5)

tangent of

y^{2} - x y - 10 = 0, (- 3, - 5)

y = \frac{5}{7} x - \frac{20}{7}

Solution steps

Find the slope of

y^{2} - x y - 10 = 0 : \frac{d y}{d x} = \frac{y}{2 y - x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{7}

Find the line with slope m=

\frac{5}{7}

and passing through

(- 3, - 5) : y = \frac{5}{7} x - \frac{20}{7}

y = \frac{5}{7} x - \frac{20}{7}

What is the tangent of y^2-xy-10=0,(-3,-5) ?
The tangent of y^2-xy-10=0,(-3,-5) is y= 5/7 x-20/7