What is the tangent of f(x)=6e^xcos(x),\at x=0 ?

The tangent of f(x)=6e^xcos(x),\at x=0 is y=6x+6

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tangent of f(x)=6e^xcos(x),\at x=0

tangent of

f (x) = 6 e^{x} cos (x), at x = 0

y = 6 x + 6

Solution steps

Find the tangent point:

(0, 6)

Find the slope of

f (x) = 6 e^{x} cos (x) : \frac{df ( x )}{d x} = 6 (e^{x} cos (x) - e^{x} sin (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(0, 6) : y = 6 x + 6

y = 6 x + 6

What is the tangent of f(x)=6e^xcos(x),\at x=0 ?
The tangent of f(x)=6e^xcos(x),\at x=0 is y=6x+6