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Popular Calculus >

f(t)=sqrt(2t+1)

Solution

f (t) = 2 t + 1

Solution

Domain : t \geq - \frac{1}{2}

Range : f (t) \geq 0

X Intercepts : (- \frac{1}{2}, 0), Y Intercepts : (0, 1)

Asymptotes : None

Extreme Points : Minimum (- \frac{1}{2}, 0)

+1

Interval Notation

Domain : [- \frac{1}{2}, \infty)

Range : [0, \infty)

Solution steps

Domain of

2 t + 1 : t \geq - \frac{1}{2}

Range of

2 t + 1 : f (t) \geq 0

Axis interception points of

2 t + 1 :

X Intercepts

: (- \frac{1}{2}, 0),

Y Intercepts

: (0, 1)

Asymptotes of

2 t + 1 :

None

Extreme Points of

2 t + 1 :

Minimum

(- \frac{1}{2}, 0)

Graph

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Frequently Asked Questions (FAQ)

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