What is (\partial)/(\partial x)(x^2+(y-1)^2) ?

The answer to (\partial)/(\partial x)(x^2+(y-1)^2) is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(x^2+(y-1)^2)

\frac{\partial}{\partial x} (x^{2} + (y - 1)^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + (y - 1)^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} ((y - 1)^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} ((y - 1)^{2}) = 0

= 2 x + 0

Simplify

= 2 x

What is (\partial)/(\partial x)(x^2+(y-1)^2) ?
The answer to (\partial)/(\partial x)(x^2+(y-1)^2) is 2x