(xydy)/(dx)+y^2=2x

Lösung

\frac{x y d y}{d x} + y^{2} = 2 x

y = \frac{4 x ^{3} + c _{1}}{3 x}, y = - \frac{4 x ^{3} + c _{1}}{3 x}

Schritte zur Lösung

\frac{x y d y}{d x} + y^{2} = 2 x

Solve Bernoulli ODE:

y = \frac{4 x ^{3} + c _{1}}{3 x}, y = - \frac{4 x ^{3} + c _{1}}{3 x}

y = \frac{4 x ^{3} + c _{1}}{3 x}, y = - \frac{4 x ^{3} + c _{1}}{3 x}

\frac{d}{d x} (\frac{1 - x e ^{x}}{x + e ^{x}})

a re a y = e^{x}, y = x, x = 0, x = 2

\int \frac{( x ^{2} + 1 )}{( x - 5 ) ( x - 4 ) ^{2}} d x

\frac{d}{d x} (- \frac{1}{2 ( 1 + x ) ^{\frac{3}{2}}})

\int_{\frac{1}{4}}^{7} \frac{9}{3 4 x - 1} d x