What is (\partial)/(\partial x)(x+y^2+xy+3) ?

The answer to (\partial)/(\partial x)(x+y^2+xy+3) is y+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(x+y^2+xy+3)

\frac{\partial}{\partial x} (x + y^{2} + x y + 3)

y + 1

Solution steps

\frac{\partial}{\partial x} (x + y^{2} + x y + 3)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (3)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (3) = 0

= 1 + 0 + y + 0

Simplify

= y + 1

What is (\partial)/(\partial x)(x+y^2+xy+3) ?
The answer to (\partial)/(\partial x)(x+y^2+xy+3) is y+1