What is the derivative of ax^2+bx ?

The derivative of ax^2+bx is 2ax+b

What is the first derivative of ax^2+bx ?

The first derivative of ax^2+bx is 2ax+b

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\frac{d}{d x} (a x^{2} + b x)

2 a x + b

Solution steps

\frac{d}{d x} (a x^{2} + b x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x^{2}) + \frac{d}{d x} (b x)

\frac{d}{d x} (a x^{2}) = 2 a x

\frac{d}{d x} (b x) = b

= 2 a x + b

What is the derivative of ax^2+bx ?
The derivative of ax^2+bx is 2ax+b
What is the first derivative of ax^2+bx ?
The first derivative of ax^2+bx is 2ax+b