en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

y=x^2ln(2x+1)

Solution

y = x^{2} ln (2 x + 1)

Solution

Domain : x > - \frac{1}{2}

Range : - \infty < f (x) < \infty

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = - \frac{1}{2}

Extreme Points : None

+1

Interval Notation

Domain : (- \frac{1}{2}, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

x^{2} ln (2 x + 1) : x > - \frac{1}{2}

Range of

x^{2} ln (2 x + 1) : - \infty < f (x) < \infty

Axis interception points of

x^{2} ln (2 x + 1) :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

x^{2} ln (2 x + 1) :

Vertical

: x = - \frac{1}{2}

Extreme Points of

x^{2} ln (2 x + 1) :

None

Graph

Popular Examples

derivative of 1/((x+1^3(3x-1)^2))

derivative of (x/2 ^4)

derivative of y(θ)= pi/7 cos(θ)

integral of (3x+1)/(x^3-x^2+x-1)

integral of e^xsin(y)

Frequently Asked Questions (FAQ)

What is the y=x^2ln(2x+1) ?
The y=x^2ln(2x+1) is