What is the tangent of f(x)=2e^xcos(x),\at x=0 ?

The tangent of f(x)=2e^xcos(x),\at x=0 is y=2x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=2e^xcos(x),\at x=0

tangent of

f (x) = 2 e^{x} cos (x), at x = 0

y = 2 x + 2

Solution steps

Find the tangent point:

(0, 2)

Find the slope of

f (x) = 2 e^{x} cos (x) : \frac{df ( x )}{d x} = 2 (e^{x} cos (x) - e^{x} sin (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(0, 2) : y = 2 x + 2

y = 2 x + 2

What is the tangent of f(x)=2e^xcos(x),\at x=0 ?
The tangent of f(x)=2e^xcos(x),\at x=0 is y=2x+2