integral from 7 to 9 of (x^2+2x-3)

解

\int_{7}^{9} (x^{2} + 2 x - 3) d x

\frac{464}{3}

十進法表記

154.66666 \dots

解答ステップ

\int_{7}^{9} x^{2} + 2 x - 3 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{7}^{9} x^{2} d x + \int_{7}^{9} 2 x d x - \int_{7}^{9} 3 d x

\int_{7}^{9} x^{2} d x = \frac{386}{3}

\int_{7}^{9} 2 x d x = 32

\int_{7}^{9} 3 d x = 6

= \frac{386}{3} + 32 - 6

簡素化

\frac{386}{3} + 32 - 6 : \frac{464}{3}

= \frac{464}{3}