What is the solution for x^2dy-2xydx=x^4cos(2x)dx ?

The solution for x^2dy-2xydx=x^4cos(2x)dx is y= 1/2 sin(2x)x^2+c_{1}x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

x^2dy-2xydx=x^4cos(2x)dx

x^{2} d y - 2 x y d x = x^{4} cos (2 x) d x

y = \frac{1}{2} sin (2 x) x^{2} + c_{1} x^{2}

Solution steps

x^{2} d y - 2 x y d x = x^{4} cos (2 x) d x

Solve linear ODE:

y = \frac{1}{2} sin (2 x) x^{2} + c_{1} x^{2}

y = \frac{1}{2} sin (2 x) x^{2} + c_{1} x^{2}

What is the solution for x^2dy-2xydx=x^4cos(2x)dx ?
The solution for x^2dy-2xydx=x^4cos(2x)dx is y= 1/2 sin(2x)x^2+c_{1}x^2